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  4. In an isothermal process at 300 K, 1 mole of an ideal gas expands from a pressure 100 atm against an external pressure of 50 atm. Then total entropy change (Cal K- 1 ) in the process is -

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Q. In an isothermal process at 300 K, 1 mole of an ideal gas expands from a pressure 100 atm against an external pressure of 50 atm. Then total entropy change (Cal $K^{- 1}$ ) in the process is -

NTA AbhyasNTA Abhyas 2020Thermodynamics

Solution:

$\Delta S_{s y s}=1\times 2\times 2.303log\frac{100}{50}\sim eq1.39 \, Cal \, K^{- 1}$

$\Delta S_{s u r r}=\frac{- 1 \times 2 \times 300 \left(1 - \frac{50}{100}\right)}{300}=-1.0 \, Cal \, K^{- 1}$

$\Delta S_{t o t a l}=+0.39calK^{- 1}$