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Q.
In an isobaric process, heat is supplied to a monoatomic ideal gas. The fraction of heat that goes into mechanical work is
NTA AbhyasNTA Abhyas 2020Thermodynamics
Solution:
$Q_{P}=nC_{P}\Delta T=\frac{5}{2}nR\Delta TW=P\Delta V=nR\Delta T\Rightarrow \frac{W}{Q_{P}}=\frac{n R \Delta T}{\frac{5}{2} n R \Delta T}=\frac{2}{5}$