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Q.
In an interference, the intensity of two interfering waves are $I$ and $4I $ respectively. They produce intensity at two points A and B with phase angle of $\pi$/2 and $\pi$ respectively. Then difference in between them is
Resultant intensity,
$I=I_{1}+I_{2}+2\sqrt{I_{1}I_{2}}cos\, \phi$
Here, $I_{1}=I,I_{2}=4I,\phi_{1}=\frac{\pi}{2}$ and $\phi_{2}=\pi$
At A intensity,
$I_{A}=I+4I+2\sqrt{4I^{2}}\,cos \frac{\pi}{2}=5I$
At B intensity,
$I_{B}=I+4I+2\sqrt{4I^{2}}cos \pi=5I-4I=I$
Therefore, difference between intensities is
$I_{A}-I_{B} = 5I-I = 4I$