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  4. In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm . What should be the wavelength of the light source in order to obtain 5th bright fringe at the same point ?

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Q. In an interference experiment, third bright fringe is obtained at a point on the screen with a light of $ 700\, nm $ . What should be the wavelength of the light source in order to obtain $ 5th $ bright fringe at the same point ?

MHT CETMHT CET 2009

Solution:

$n_{1} \lambda_{1}= n_{2} \lambda_{2}$
$\Rightarrow 3 \times 700=5 \times \lambda_{2}$
$\Rightarrow \lambda_{2}=420 nm$