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Q. In an interference experiment, third bright fringe is obtained at a point on the screen with a light of $700\, nm$. What should be the wavelength of the light in order to obtain $5^{th}$ bright fringe at the same point ?

Wave Optics

Solution:

$3^{rd} \max$. of $\lambda_{1}=5^{th} \max$. of $\lambda_{2}$
$\frac{3 \lambda_{1} D }{ d }=\frac{5 \lambda_{2} D }{ d }$
$\Rightarrow \lambda_{2}=\frac{3}{5}(700)=420\, nm$