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  4. In an explosion a body breaks up into pieces of unequal masses. In this case

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Q. In an explosion a body breaks up into pieces of unequal masses. In this case

ManipalManipal 2011System of Particles and Rotational Motion

Solution:

From law of conservation of linear momentum
i.e., final momentum = initial momentum
$m_{ q } v_{1}+m_{2} v_{2}=0$ ...(i)
where $m_{1}$ and $m_{2}$ are masses of pieces.
(initial momentum is zero because body is stationary)
From Eq. (i), $m_{1},v_{1}=-m_{2} v_{2}$
So, numerical value of momentum of both pieces will be equal.