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Q. In an experiment four quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows $P = \frac{a^3 b^2}{cd}$ % error in P is :-

NEETNEET 2013Physical World, Units and Measurements

Solution:

P = $\frac{a^3 b^2}{ cd} \frac{\Delta P}{P} = \pm \left (3 \frac{\Delta a}{a} + 2\frac{\Delta b}{b} + \frac{\Delta c}{c} + \frac{\Delta d}{d}\right)$
$= \pm(3 \times 1 + 2 \times 2 + 3+ 4)$
=$\pm 14 %$