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  4. In an experiment for determination of refractive index of glass of a prism by i - δ , plot, it was found that a ray incident at angle 35°, suffers a deviation of 40° and that it emerges at angle 79°. Ιn that case which of the following is closest to the maximum possible value of the refractive index ?

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Q. In an experiment for determination of refractive index of glass of a prism by $i - \delta $ , plot, it was found that a ray incident at angle $35^{\circ}$, suffers a deviation of $40^{\circ}$ and that it emerges at angle $79^{\circ}$. Ιn that case which of the following is closest to the maximum possible value of the refractive index ?

JEE MainJEE Main 2016Ray Optics and Optical Instruments

Solution:

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$\delta = i + e - A$
$40 = 35 + 79 - A$
$40 = 114 - A$
$A = 114 - 40 = 74 = r_1 + r_2$
From this we get,
$\mu = 1.5$
$\therefore \, \, \delta_{min} < 40^{\circ}$
$\mu < \frac{\sin \left(\frac{70 + 40}{2} \right)}{\sin 37}$
$\therefore \, \, \mu_{max} = 1.44$