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Q. In an experiment according to set up, when $E_{1}=12 \, V$ and internal resistance zero, $e=2 \, V$ . The galvanometer reads zero, then $X$ would be-
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NTA AbhyasNTA Abhyas 2022

Solution:

Voltage across $X$ is $2 v$
$\text { So }\left(\frac{E_1}{500+X}\right) X=2$
$\Rightarrow\left(\frac{12}{500+X}\right) X=2 $
$\Rightarrow 12 X=1000+2 X $
$\Rightarrow 10 X=1000$
$ X =100 \,\Omega$