Question

In an exothermic reaction at $10^{\circ} C$ rise in temperature will:

• A. decrease the value of equilibrium constant
• B. double the value of $ K_{c}$
• C. do not produce any change in $ K_{c} $
• D. produce some change in $ K_{c} $

Answer 1

Answer: (A)

Equilibrium constant for a reversible reaction is given as: $K_{c}=\frac{k_{f}}{k_{b}}$
In the exothermic reaction, the backward reaction increases more rapidly with increasing temperature than the forward reaction.
Therefore, the value of equilibrium constant is reduced.