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Q. In an electrical field, the particles of a colloid system move towards cathode. The coagulation of the same sol is studied using $K_2SO_4(I), Na_3PO_4 (II), K_4[Fe(CN)_6] (III)$ and $NaCl (IV)$. The coagulating power should be

Surface Chemistry

Solution:

The given sol is positively charged because the colloidal particles move towards cathode. Its coagulation can be caused by oppositely charged anion therefore, the coagulating power is
$\left[Fe\left(CN\right)_{6}\right]^{4-} > PO_{4}^{3-} > SO_{4}^{2-} > Cl^{-}$