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Q. In an atom, an electron is moving with a speed of $600\,m/s$ with an accuracy of $0.005\%.$ Certainity with which the position of the electron can be located is ($h = 6.6 × 10^{−34} kg\, m^2\,s^{−1}$ , mass of electron, $e_m = 9.1×10^{− kg}$ )

AIEEEAIEEE 2009Structure of Atom

Solution:

$\Delta x.m\,\Delta v=\frac{h}{4\pi}$
$\Delta x=\frac{h}{4\pi\,m\Delta v}$
$\Delta v=600\times\frac{0.005}{100}=0.03$
$\Rightarrow \Delta x=\frac{6.625\times10^{-34}}{4\times3.14\times9.1\times10^{-31}\times0.03}=1.92\times10^{-3}\,m$