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  4. In an AC circuit, peak value of voltage is 423 volts. Its effective voltage is

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Q. In an AC circuit, peak value of voltage is $423$ volts. Its effective voltage is

Alternating Current

Solution:

Effective voltage, $V_{\text {r.m.s. }}=\frac{V_{o}}{\sqrt{2}}$
$=\frac{423}{\sqrt{2}}=300\,V$