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  3. Physics
  4. In an A.C. circuit, the current flowing is I=5 sin (100 t - π/2) ampere and the potential difference is V = 200 sin (100 t) volts. The power consumption is equal to

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Q. In an A.C. circuit, the current flowing is $I=5 \, \sin \, (100 t - {\pi/2})$ ampere and the potential difference is V = 200 sin (100 t) volts. The power consumption is equal to

AIPMTAIPMT 1995

Solution:

Current $(I) = 5 \sin (100 t - {\pi/2})$ and voltage (V)
$= 200 \, sin \, (100 t)$. Comparing the given equation,
with the standard equation, we find that between
current and voltage is $\phi=\frac{\pi}{2}=90^\circ.$
Power consumption $P=I_{rms}V_{rms}cos \phi$
$ \, \, \, \, \, \, \, \, =I_{rms}V_{rms}cos90^\circ=0$