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  4. In alkaline medium, KMnO4 reacts as follows 2 KMnO 4+2 KOH arrow 2 K 2 MnO 4+ H 2 O +[O] Therefore, the equivalent weight of K MnO 4 will be

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Q. In alkaline medium, $KMnO_4$ reacts as follows
$2 KMnO _{4}+2 KOH \rightarrow 2 K _{2} MnO _{4}+ H _{2} O +[O]$
Therefore, the equivalent weight of $K MnO _{4}$ will be

BHUBHU 2010

Solution:

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Equivalent wt. of $KMnO _{4}=\frac{\text { molecular weight }}{n}$
$=\frac{158}{1}=158.0$