Question

In alkaline medium $ClO_{2}$ oxidises $H_{2}O_{2}$ to $O_{2}$ and itself gets reduced to $Cl^{-},$ $X$ moles of $H_{2}O_{2}$ are oxidised by $1$ mole of $ClO_{2}$ . Calculate $2X$ ?

Answer 1

The balanced chemical equation is $2ClO_{2}​+5H_{2}O_{2}​+2OH^{-} \rightarrow 2Cl^{-}+5O_{2}​+6H_{2}O$
$2molClO_{2}​=5molH_{2}O_{2}​$
$1molClO_{2 ​}=2.5molH_{2}O_{2}​2X=2\times 2.5=5$