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Q. In AC series circuit, the resistance, inductive reactance and capacitance reactance are $3 \Omega, 10 \Omega, 14 \Omega$ respectively. The impedence of the circuit is:

Alternating Current

Solution:

Here, Resistance, $R =3 \Omega$
Inductive reflectance, $X_{L}=10 \Omega$
Capacitive reactance, $X_{c}=14 \Omega$
The impedence of the series LCR circuit is:
$Z=\sqrt{R^{2}+\left(X_{C}-X_{L}\right)^{2}}$
$=\sqrt{(3)^{2}+(14-10)^{2}}$
$Z=5 \Omega$