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Q. In a Young's double slit experiment the spacing between the slits is $0.3\, mm$ and the screen is kept at a distance of $1.5\, m$. The second bright fringe is found to be displaced by $6\, mm$ from the central fringe. The wavelength of the light (in $nm$ ) used in the experiment is

Wave Optics

Solution:

According to question
$2 \beta=6\, mm$ where $\beta=\frac{\lambda D}{d}$
$\Rightarrow \lambda=\frac{(6\, mm )(0.3\, mm )}{2(1.5\, m )}$
$=6 \times 10^{-7} m =600\, nm$