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Q. In a Young's double slit experiment, $I_{o}$ is the intensity at the central maximum and $\beta$ is the fringe width. The intensity at a point $P$ distant $x$ from the centre will be

Wave Optics

Solution:

Path difference at point $P=\frac{x d}{D}$
Phase difference at point $P=\frac{2 \pi}{\lambda} \frac{x d}{D}=\frac{2 \pi x}{\beta}$
$I_{0}=4 I_{1}$, intensity at point $P$
$I=I_{1}+I_{1}+2 I_{1} \cos \frac{2 \pi x}{\beta}=2 I_{1}\left[1+\cos \frac{2 \pi x}{\beta}\right]$
$=I_{0} \cos ^{2} \frac{\pi x}{\beta}$