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Q.
In a wave, the path difference corresponding to a phase difference of $\phi$ is
Wave Optics
Solution:
Phase difference of $2 \pi$ corresponds to path difference of $\lambda$. So, unit phase difference corresponds to $\frac{\lambda}{2 \pi}$. Clearly, the phase difference $\phi$ corresponds to a path difference of $\frac{\lambda}{2 \pi} \phi$