1. Tardigrade
  2. Question
  3. Physics
  4. In a vernier callipers, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be..... × 10-2 mm.

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. In a vernier callipers, each $cm$ on the main scale is divided into $20$ equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be..... $\times 10^{-2} mm$.

JEE MainJEE Main 2022Physical World, Units and Measurements

Solution:

$20\, MSD =1\, cm$
$1\, MSD =\frac{1}{20} cm$
$10\, VSD =9\, MSD$
$1\, VSD =\frac{9}{10} MSD$
$=\frac{9}{10} \times \frac{1}{20} cm$
$1\, VSD =\frac{9}{200} cm$
$VC =1\, MSD -1 \, VSD$
$=\frac{1}{20} cm -\frac{9}{200} cm$
$=\frac{1}{200} \times 10\, mm$
$VC =5 \times 10^{-2} mm$