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  4. In a titration, 25 cm3 of 0.1 N oxalic acid solution requires 20 cm3 of sodium hydroxide for complete neutralization. The mass of sodium hydroxide in 250 cm3 solution is

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Q. In a titration, 25 $cm^3$ of 0.1 N oxalic acid solution requires 20 $cm^3$ of sodium hydroxide for complete neutralization. The mass of sodium hydroxide in 250 $cm^3$ solution is

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Solution:

Oxalic acid                                          NaOH
$V_1 = 25\, cm^3, N_1 = 0.1\, N$     $V_2 = 20\, cm^3, N_2 =?$
$N_1V_1 = N_2V_2$
$0.1 \times 25 = N_2 \times 20$
$N_2 = 0.125\, N$
$N = \frac{w \times 100}{Eq.wt \times V} \Rightarrow 0.125 = \frac{w \times 1000}{40 \times 250}$
$ \Rightarrow \:\: w = 1.25 \, g$