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Q. In a single-slit diffraction pattern, the position of first secondary maximum is at $30^{\circ }$ , then what will be the angular position of second minima?

NTA AbhyasNTA Abhyas 2022

Solution:

For first secondary maxima,
$\sin\left(\theta \right)_{1}=\left(1 + \frac{1}{2}\right)\frac{\lambda }{a}=\frac{3 \lambda }{2 a}$ $\Rightarrow \sin30^{o}=\frac{3 \lambda }{2 a}$
$\Rightarrow \frac{\lambda }{a}=\frac{1}{3}$
For second minima,
$\sin \theta =\frac{2 \lambda }{a}=\frac{2}{3}$
or $\theta =\left(\sin\right)^{- 1} \, \left(2 / 3\right)$