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  4. In a single slit diffraction pattern-the distance between the first minimum on the left and the first minimum on the right is 5 mm. The Screen on which the diffraction pattern is displayed at a distance of 80 cm from the slit The length is 6000 overset texto mathop textA .The slit width in (mm) is about:

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Q. In a single slit diffraction pattern-the distance between the first minimum on the left and the first minimum on the right is 5 mm. The Screen on which the diffraction pattern is displayed at a distance of 80 cm from the slit The length is $ 6000\overset{\text{o}}{\mathop{\text{A}}}\, $ .The slit width in (mm) is about:

KEAMKEAM 2000

Solution:

Slit width, $ W=\frac{D\lambda }{d} $ Given, $ D=80\text{ }cm=80\times {{10}^{-2}}m, $ $ \lambda =6000{\AA}=6000\times {{10}^{-10}}m, $ $ d=\frac{5}{2}mm=\frac{5\times {{10}^{-3}}}{2}m $ $ \therefore $ $ W=\frac{80\times {{10}^{-2}}\times 6000\times {{10}^{-10}}\times 2}{5\times {{10}^{-3}}} $ $ W=0.192\times {{10}^{-3}}m=0.192\,mm $