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Q.
In a showing figure find the equivalent resistance between $A$ and $B$.
Rajasthan PMTRajasthan PMT 2002
Solution:
The figure can be shown as equivalent resistance of $R_{1}, R_{2}$ and $R_{3}$
$R'=R_{1}+R_{2}+R_{3}$
$=5+5+5=15 \,\Omega$
Equivalent resistance of $R_{4}, R_{5}$, and $R_{6}$
$R''=5+5+5=15 \Omega$
$R_{ AB }=\frac{R' R''}{R'+R''}$
$=\frac{15 \times 15}{15+15}=\frac{15}{2}$
$=7.5\, ohm$