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Q. In a shotput event an athlete throws the shotput of mass $ 20\, kg $ with an initial speed of $ 2\,ms^{-1} $ at $ 45^° $ from a height $ 3\, m $ above ground. Assuming air resistance to be negligible and acceleration due to gravity to be $ 10\, ms ^{-2}$ , the kinetic energy of the shotput when it just reaches the ground will be

Work, Energy and Power

Solution:

Using law of energy conservation,
$ (TME)_i = (TME)_f $
$ \Rightarrow U_{i} + K_{i}=U_{f }+K_{f} $
$ \Rightarrow 20 \times 10 \times 3 +\frac{1}{2} \times 20 \times2^{2} $
$ = 0 + K_{f} $
$ \Rightarrow K_{f} = 640\,J $