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  4. In a series L C R circuit the voltage across resistance, capacitance and inductance is 10 V each. If the capacitance is short circuited, the voltage across the inductance will be

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Q. In a series $L C R$ circuit the voltage across resistance, capacitance and inductance is $10\, V$ each. If the capacitance is short circuited, the voltage across the inductance will be

AIIMSAIIMS 2000Alternating Current

Solution:

Since voltage across L, C and R is same, equal to 10 V, therefore R = XL = XC.
Also total voltage in the circuit is
I [R2 + (XL - XC )2]1/2 = I R = 10 V.
When capacitor is short circuited current in the circuit
$I=\frac{10}{\left(R^{2}+X_{L}^{2}\right)^{1/2}}=\frac{10}{\sqrt{2}R}.$
Potential drop across inductance
$=IX_{L}=IR=10/\sqrt{2}$ V.