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Q.
In a sample of radioactive material, what fraction of the initial number of active nuclei will remain disintegrated after half of a half-life of the sample?
BHUBHU 2010
Solution:
According to radioactive decay, $\frac{N}{N_{0}}=\left(\frac{1}{2}\right)^{t / T_{1 / 2}}$
According to question, $t=\frac{T_{1 / 2}}{2}$
Then, $\frac{N}{N_{0}}=\left(\frac{1}{2}\right)^{1 / 2}=\frac{1}{\sqrt{2}}$