Question

In a resonance pipe the first and second resonance are obtained at depths $\text{22} \text{.7 cm}$ and $\text{70} \text{.2 cm}$ respectively. What will be the end correction?

• A. $\text{1} .0 \text{5 cm}$
• B. $\text{115} \text{.5 cm}$
• C. $\text{92} \text{.5 cm}$
• D. $\text{113} \text{.5 cm}$

Answer 1

Answer: (A)

For the end correction $x$ ,
$\Longrightarrow \, \, \, x=\frac{l_{2} - 3 l_{1}}{2}$
$=\frac{70.2 - 3 \times 22.7}{2}=1.05cm$