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Q.
In a region, $10^{19} \alpha$ -particles and $10^{19}$ protons move to the left, while $10^{19}$ electrons move to the right per second. The current is
Current Electricity
Solution:
An $\alpha$ -particle has a charge equal to 2 protons and 2 neutrons. Motion of $\alpha$ -particle to the left, motion of proton towards left and motion of electrons towards right, all will produce conventional current towards left. The total current will be
$i=10^{19} \times\left(2 \times 1.6 \times 10^{-19}\right)+10^{19}$
$\times\left(1.6 \times 10^{-19}\right)+10^{19} \times\left(1.6 \times 10^{-19}\right)=6.4 \,A$