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Q.
In a reaction, the initial conc. of the reactants increases four fold and rate becomes eight times of its initial value, order of reactions is
NTA AbhyasNTA Abhyas 2022
Solution:
Let the rate law be
$\text{r} = \text{k} \left(\right. \text{c} \left.\right)^{\text{n}} \, ... \, \left(\right. \text{i} \left.\right)$
on increasing concentration
$8\text{r}=\text{k}\left(4 \text{c}\right)^{n}$ ... (ii)
$2^{3}=2^{2 \text{n}}$
$2\text{n}=3$
$\text{n}=1.5$