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  4. In a reaction, Na2S2O3 is converted to Na2S4O6, equivalent weight of Na2S2O3 for this reaction is (mol. wt of Na2S2O3 = M)

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Q. In a reaction, $Na_2S_2O_3$ is converted to $Na_2S_4O_6$, equivalent weight of $Na_2S_2O_3$ for this reaction is (mol. wt of $Na_2S_2O_3 = M)$

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Solution:

$2Na_2S_2O_3 \to Na_2S_4O_6 + 2Na$
Mol. wt. of $Na_2S_2O_3 = M$
For this reaction, oxidation state of $1$ atom of sulphur on the left side is $+2$ and on the right hand side of the equation, is $2.5$. So, difference is $0.5$.
Valency factor = no. of atoms $\times$ change in oxidation number
$= 2 \times 0.5 = 1$
$\therefore $ Equivalent weight $= M$