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Q. In a reaction carried out at $400K$ , $0.01\%$ of the total number of collisions is effective. The energy of activation of the reaction is

NTA AbhyasNTA Abhyas 2020Chemical Kinetics

Solution:

$K=Ae^{- \frac{E_{a}}{R T}}$

$e^{\frac{E_{a}}{R T}}=\frac{0.01}{100}\Rightarrow \frac{E_{a}}{R T}=2.303log 10^{- 4}$

$\Rightarrow E_{a}=2.303\times 4\times 400=30.6kJ/mol$