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Q. In a reaction, $2 x \rightarrow y$, the concentration of $x$ decreases from $3.0\, M$ to $1.5\, M$ in $4\, \min$. The rate of the reaction is

Chemical Kinetics

Solution:

Rate of reaction $=-\frac{1}{2} \frac{d[x]}{d t}$
$=-\frac{1}{2} \frac{[1.5-3.0]}{4}$
$=\frac{1.5}{8}=0.1875\, M\, \min ^{-1}$