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  4. In a random DNA sequence, what is the lowest frequency of encountering a stop codon?

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Q. In a random DNA sequence, what is the lowest frequency of encountering a stop codon?

KVPYKVPY 2015

Solution:

Genetic codes are triplet. So, the total number of codon $=64$. Out of these there is one start (coding for methionine) codon and three stop codons (i.e. do not code for any amino acid).
$\therefore $ Functional codon $=64-3=61$
$\therefore $ Frequency of encountering stop codon
$=\frac{3}{61}=\frac{1}{20}$ approx.