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Q. In a properly adjusted tangent galvanometer ,the deflection for 1 A current , is found to be $30^\circ$. Now the Coil is turned through $90^\circ$ about vertical axis, the deflection for , the same current will be

Moving Charges and Magnetism

Solution:

The basic concept used here is that force in the coil increases as its angle of twist increases as $F \propto$ $\theta$.
Now this force in the spring will be balanced by the force due to magnetic field.
Here the correct answer will be $0^{\circ}$ because in case of $90^{\circ}$ deflection when the current is passed there will be no more deflection since it is already been more that $30^{0}$.