1. Tardigrade
  2. Question
  3. Physics
  4. In a process the pressure of a gas is inversely proportional to the square of the volume. If temperature of the gas increases, then work done by the gas

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. In a process the pressure of a gas is inversely proportional to the square of the volume. If temperature of the gas increases, then work done by the gas

Thermodynamics

Solution:

$P \propto \frac{1}{V^{2}}$
$\Rightarrow P=\frac{k}{V^{2}} V$
$\Rightarrow P V^{2}=k$
$\Rightarrow P V. V=k$
$\Rightarrow n R T V=k$
$\Rightarrow T V=k_{1}$
Since temperature increases therefore volume decrease.
Hence the work done by the gas should be negative.