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Q. In a process, molar heat capacity of a diatomic gas is $\frac {10}{3}R$. When heat Q is supplied to the gas, find the work done by it.

Solution:

$dQ = n \frac {10}{3} RdT$
$dU = \frac {5}{2} nRdT$
$\frac {dQ}{dU} = \frac {4}{3} \therefore dU = \frac {3}{4} Q$
$\therefore dW = dQ - dU$
$= Q - \frac {3}{4}Q=\frac {Q}{4}$