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Q. In a polar molecule, the ionic charge is $ 4.8\times {{10}^{-10}} $ e. s. u. If the inter ionic distance is one $ \overset{\text{o}}{\mathop{\text{A}}}\, $ unit, then the dipole moment is

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Solution:

Given ionic charge $ =4.8\times {{10}^{-10}} $ e. s. u. and ionic distance $ =1\,\overset{\text{o}}{\mathop{\text{A}}}\,={{10}^{-10}}\,\text{cm}\text{.} $ We know that dipole moment = ionic charge $ \times $ ionic distance $ =(4.8\times {{10}^{-10}})\times {{10}^{-8}} $ $ =4.8\times {{10}^{-18}}\, $ e. s. u per cm $ =4.8\,\text{debye}\text{.} $