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Q. In a photoelectric experiment, the stopping potential $V_{s}$ is plotted against the frequency v of the incident light. The resulting curve is a straight line which makes an angle $\theta $ with the v-axis. Then $tan\theta $ will be equal to

(Here $\text{E}_{\text{0}} \text{=}$ work function of the surface)

NTA AbhyasNTA Abhyas 2020Structure of Atom

Solution:

$E_{K}=hv-\phi$

$eV_{s}=hv-\phi$

$V_{s}=\frac{h v}{e}-\frac{\phi}{e}$ …(i)

$y=mx+C$ …(ii)

Comparison of equation (i) and (ii) shows that the slope i.e., $tan\theta $ will be equal to $\frac{h}{e}$ .

$m\left(\right.Slope\left.\right)=tan\theta =\frac{h}{e}$ .