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Q. In a photoelectric experiment, electrons are ejected from metals $X$ and $Y$ by light of frequency $v$. The potential difference $V$ are required to stop the electrons is measured for various frequencies. If $Y$ has a greater work function than $X$, which graph illustrates the expected results?

Dual Nature of Radiation and Matter

Solution:

$ eV _{s}=h v -W$
$V_{s}=\left(\frac{h}{e}\right) v-\left(\frac{W}{e}\right)$
$V_{s}$ vs $v$ graph is a straight line with constant slope $=\frac{h}{e}$
$\Rightarrow X$ and $Y$ will be parallel.
When $V_{s}=0, v_{0}=\left(\frac{W}{h}\right)$
As $W_{Y}>W_{X} \Rightarrow v_{0 Y}>v_{0 x}$
It means the $v$ intercept of $Y$ graph will be larger than the $v$-intercept of $X$ graph.