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  4. In a p-n-p transistor working as common base amplifier, current gain is 0.96 and emitter current is 7.2 mA. Then base current will be:

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Q. In a p-n-p transistor working as common base amplifier, current gain is 0.96 and emitter current is 7.2 mA. Then base current will be:

JIPMERJIPMER 1998

Solution:

Here, current gain $ \alpha =0.96 $ and emitter current $ {{i}_{e}}=7.2\,mA $ from the relation of current gain $ \alpha =0.96=\frac{{{I}_{c}}}{{{I}_{e}}}=\frac{{{I}_{c}}}{7.2}, $ So $ {{I}_{c}}=0.96\times 7.2=6.91\,mA $ Hence the base current $ {{I}_{b}}={{I}_{e}}-{{I}_{c}}=7.2-6.91=0.29\,mA $