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Q. In a p-n junction diode, the increase in forward voltage of 0.19 V increases the forward current by 37.6 mA. The dynamic resistance of the junction is

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

$r_{a . c}=\frac{\Delta V}{\Delta I}=\frac{0.19 V}{37.6 m A}$
$=5 \,ohm$