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  4. In a neon discharge tube 2.9 × 1018 Ne ions move to the right each second, while 1.2 × 1018 electrons move to the left per sec, electron charge is 1.6 × 10-19 C. The current in the discharge tube is

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Q. In a neon discharge tube $2.9 \times 10^{18}\, Ne$ ions move to the right each second, while $1.2 \times 10^{18}$ electrons move to the left per sec, electron charge is $1.6 \times 10^{-19} C$. The current in the discharge tube is

Chhattisgarh PMTChhattisgarh PMT 2004

Solution:

In the two cases current is flowing in the right direction,
therefore total current $I=I_{N e^{+}}+I_{e}$
or $I=\left(N_{N e^{+}}+N_{e}\right) e$ or
$I=\left(2.9 \times 10^{18}+1.2 \times 10^{18}\right) \times 1.6 \times 10^{-19}$
$ \Rightarrow I=0.66 \,A$ A towards right