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Q. In a multi-electron atom, which of the following orbitals • described by the three quantum numbers will have the same energy in the absence of magnetic and electric fields ?
(A) $n = 1,\,l = 0, \,m = 0$
(B) $n = 2,\,l = 0, \,m = 0$
(C) $n = 2, \,l = 1,\, m = 1$
(D) $n = 3,\,l = 2,\, m = 1$
(E) $n = 3,\,l = 2, \,m = 0$

AIEEEAIEEE 2005Structure of Atom

Solution:


(A) 1s $ \quad$$ \quad$(B) 2s
(C) 2p $ \quad$$ \quad$(D) 3d
(E) 3d
In the absence of any field, 3 d in (D) and (E) will be of equal energy.