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Q. In a metre bridge experiment null point is obtained at $20\, cm$ from one end of the wire when resistance $X$ is balanced against another resistance $Y$. If $X < Y$, then where will be the new position of the null point from the same end, if one decides to balance a resistance of $4X$ against $Y$ ?

AIEEEAIEEE 2004Current Electricity

Solution:

We have from meter bridge experiment,
$\frac{R_{1}}{R_{2}} = \frac{\ell_{1}}{\ell_{2}}$, where $\ell_{2} = \left(100-\ell_{1}\right)cm$
In the first case, $X/Y = 20/80$
In the second case $\frac{4X}{Y} = \frac{\ell}{100-\ell}$
$\ell = 50 \,cm.$