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Physics
In a meter bridge experiment, the ratio of the left gap resistance to right gap resistance is 2:3, the balance point from left is
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Q. In a meter bridge experiment, the ratio of the left gap resistance to right gap resistance is $ 2:3, $ the balance point from left is
J & K CET
J & K CET 2007
Current Electricity
A
60 cm
8%
B
50 cm
8%
C
40 cm
80%
D
20 cm
4%
Solution:
In a meter bridge
$\frac{R_{1}}{R_{2}}=\frac{l}{100-l}$
$\frac{2}{3}=\frac{l}{(100-l)}$
$\Rightarrow 200-2 l=3 l$
$\Rightarrow 5 l=200$
$\therefore l=40\, cm$