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  4. In a marriage hall, there are 15 bulbs of 45 W, 15 bulbs of 100 W, 15 small fans of 10 W and 2 heaters of 1 kW. If the voltage of the electric main is 220 V, then the minimum fuse capacity (in A ) of the building should be

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Q. In a marriage hall, there are $15$ bulbs of $45 \, W,$ $15$ bulbs of $100 \, W,$ $15$ small fans of $10 \, W$ and $2$ heaters of $1 \, kW.$ If the voltage of the electric main is $220 \, V,$ then the minimum fuse capacity (in $A$ ) of the building should be

NTA AbhyasNTA Abhyas 2020Current Electricity

Solution:

Total power is

$\left(\right.15\times 45\left.\right)+\left(\right.15\times 100\left.\right)+\left(\right.15\times 10\left.\right)+\left(\right.2\times 1000\left.\right)=4325 \, W$
So current is $=\frac{4325}{220}=19.66 \, A$
Ans is $20 \, A$