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  4. In a large building, there are 15 bulbs of 40 W, 5 bulbs of 100 W, 5 fans of 80 W and 1 heater of 1 kW. The voltage of the electric mains is 220 V. The minimum capacity of the main fuse of the building will be :

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Q. In a large building, there are 15 bulbs of 40\, W, 5 bulbs of 100 W, 5 fans of $80\, W$ and 1 heater of $1\, kW$. The voltage of the electric mains is $220 \,V$. The minimum capacity of the main fuse of the building will be :

JEE MainJEE Main 2014Current Electricity

Solution:

$15 \times 40+5 \times 100+5 \times 80+1000=V \times I $
$600+500+400+1000=220\,I $
$I=\frac{2500}{220}=11.36 $
$I=12\,A$