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Q. In a hypothetical Bohr hydrogen atom, the mass of the electron is doubled. The energy $E_0^{\prime}$ and radius $r_0^{\prime}$ of the first orbit will be ( $r _0$ is the Bohr radius)

Atoms

Solution:

As $r \propto \frac{1}{ m } $
$ \therefore r _0^{\prime}=\frac{1}{2} r _0$
As $E \propto m $
$ \therefore E _0^{\prime}=2(-13.6)=-27.2\, eV$